120v On Board Air using an inverter
I have an inverter that is rated for 400w(800w peak), has anyone ever considered using a small 120v air compressor (like a nailer size) on their rig for on board air? I want to use air tools, i realize this isn't a big enough compressor for some tools, but it will run an impact(not to it's max of course).
Seems you can pick up a decent used one for cheap. I figured i would separate the motor/pump from the tank, relocate those two pieces. I tried searching but all i get is 12v OBA. thanks |
I be really surprised if your little inverter would even start that compressor - have you tried it yet?
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No i havent tried, my father has one i was going to use a s a test. I'm guessing the start up draw is going to be more then the inverter can handle. The compressor claims to only draw 260w.
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sorry, i should mention that the inverter is installed in a truck that is not running at the moment(nor tagged), oh, and the inverter isn't actually connected to the battery yet.....i'm just thinking out loud.
thanks compressor claims 260watts, i will edit the above...mistake....amps...watts...they are the same right?...haha! |
I was thinking the same thing, I have a 400w inverter that i use to power my small round compressor that i got from HF for like 39 bucks, it works fine but needs a bigger tank, I have a larger inverter that I was thinking on installing in the rig and hooking to the compressor if i mount it somewhere in the rig. not sure what to do yet...to many choices.
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Originally Posted by RBX
(Post 51589898)
compressor claims 260watts, i will edit the above...mistake....amps...watts...they are the same right?...haha! OHM's Law: Ohm's Law defines the relationships between (P) power, (E) voltage, (I) current, and (R) resistance. One ohm is the resistance value through which one volt will maintain a current of one ampere. ( I ) Current is what flows on a wire or conductor like water flowing down a river. Current flows from negative to positive on the surface of a conductor. Current is measured in (A) amperes or amps. ( E ) or V for volts Voltage is the difference in electrical potential between two points in a circuit. It's the push or pressure behind current flow through a circuit, and is measured in (V) volts. ( R ) Resistance determines how much current will flow through a component. Resistors are used to control voltage and current levels. A very high resistance allows a small amount of current to flow. A very low resistance allows a large amount of current to flow. Resistance is measured in ohms. ( P ) Power is the amount of current times the voltage level at a given point measured in wattage or watts http://i119.photobucket.com/albums/o...g/ohms-law.gif ohms law calculator link: http://www.the12volt.com/ohm/page2.asp source for this stuff below: Calculate for Voltage (E) E = I x R E = P / I E = Square Root of (P x R) Calculate for Resistance (R) R = P / I ^2 R = E / I R = E^ 2 / P Calculate for Power (P) P = I ^2 x R P = E x I P = E ^2 / R Calculate for Current (I) I = P / E I = Square Root of (P / R) I = E / R |
I love YT. Just wait a week or less and your question will come up without even asking it.
I got a free pancake aircompressor from my boss, and can score an inverter for cheap. Poormans OBA! I will keep an eye on this thread for even more ideas. |
Originally Posted by ocdropzone
(Post 51604890)
nope here: edumacate yourself:D Watt=P, Current is Amps=I
OHM's Law: Ohm's Law defines the relationships between (P) power, (E) voltage, (I) current, and (R) resistance. One ohm is the resistance value through which one volt will maintain a current of one ampere. ( I ) Current is what flows on a wire or conductor like water flowing down a river. Current flows from negative to positive on the surface of a conductor. Current is measured in (A) amperes or amps. ( E ) or V for volts Voltage is the difference in electrical potential between two points in a circuit. It's the push or pressure behind current flow through a circuit, and is measured in (V) volts. ( R ) Resistance determines how much current will flow through a component. Resistors are used to control voltage and current levels. A very high resistance allows a small amount of current to flow. A very low resistance allows a large amount of current to flow. Resistance is measured in ohms. ( P ) Power is the amount of current times the voltage level at a given point measured in wattage or watts http://i119.photobucket.com/albums/o...g/ohms-law.gif ohms law calculator link: http://www.the12volt.com/ohm/page2.asp source for this stuff below: Calculate for Voltage (E) E = I x R E = P / I E = Square Root of (P x R) Calculate for Resistance (R) R = P / I ^2 R = E / I R = E^ 2 / P Calculate for Power (P) P = I ^2 x R P = E x I P = E ^2 / R Calculate for Current (I) I = P / E I = Square Root of (P / R) I = E / R The compressor is a good idea, subscribed to see if it works. |
Since I jet fired the truck up last night, I'll have to swing by my father's house and test his compressor. I am thinking I can mount the comp(sans tank) in the bed wall behind the seat. It will be loud in the truck but out of the elements.
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Oops I meant to say put the compressor in a safe area away from the elements and put the tank elsewhere , more convenient. Sorry
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this is old but i been looking at oba ideas and want to see if an inverter would run a small compressor?
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I haven't had a chance to test my idea yet, but I will post up when I do.
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thanks. im also looking at the 12v puma compressor with tank
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